PROBLEM DESCRIPTION
Determine whether an integer is a palindrome. Do this without extra space. A palindrome integer is an integer x for which reverse(x) = x where reverse(x) is x with its digit reversed. Negative numbers are not palindromic.
SOLUTION
One straight forward solution is to conver the int A into a String and compare check if it’s a palindrome by taking two pointers from left and right. However, we are not allowed to use extra space. So, we would need to find another way to reverse the given int without conversion.
If we know the last digit d and the number of digits c, we can place it to the position with highest value by using d * 10^(c-1).
For example: A = 567
We have the last digit 7. Number of digits c is 3.
To place it on the highest position, we can simply do: 7 x 10^2.
For the next digit 6 add 6 x 10^1 and finally 5 x 10^0.
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public class Solution {
public int isPalindrome(int A) {
if(A < 0) return 0;
return A == reverse(A) ? 1 : 0;
}
public int numberOfDigits(int A){
int count = 0;
while(A != 0){
count++;
A = A/10;
}
return count;
}
public int reverse(int A){
int res = 0;
int pow = numberOfDigits(A)-1;
while(A != 0){
int d = A%10;
A = A/10;
res = res + d * (int)Math.pow(10, pow);
pow--;
}
return res;
}
}