Problem Description
Given an array nums of distinct integers, return all the possible permutations. You can return the answer in any order.
Solution
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class Solution {
List<List<Integer>> ans = new ArrayList<List<Integer>>();
public List<List<Integer>> permute(int[] nums) {
find(nums, 0);
return ans;
}
public void save(int[] arr){
List<Integer> list = new ArrayList<>();
for(int i=0; i<arr.length; i++){
list.add(arr[i]);
}
ans.add(list);
}
public void find(int[] arr, int i){
if(i == arr.length-1){
save(arr);
return;
}
for(int j=i; j<arr.length; j++){
swap(arr, i, j);
find(arr, i+1);
swap(arr, i, j);
}
}
public void swap(int[] arr, int i, int j){
int temp = arr[i];
arr[i] = arr[j];
arr[j] = temp;
}
}
ANOTHER WAY TO CODE
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class Solution {
public List<List<Integer>> permute(int[] nums) {
return permuteHelper(nums, 0, new ArrayList<List<Integer>>());
}
// Helper function to swap elements at indices i and j in the array
public void swap(int[] nums, int i, int j){
int t = nums[i];
nums[i] = nums[j];
nums[j] = t;
}
// Helper function to generate all permutations using backtracking
public List<List<Integer>> permuteHelper(int[] nums, int i, List<List<Integer>> all){
// We are beyond the array now, so all positions have been covered
// We can add the current "state" of the nums array as one of the possible permutations
if(i == nums.length){
// Create a new list to store the current permutation
List<Integer> permutation = new ArrayList<>();
for (int num : nums) {
permutation.add(num);
}
// Add the current permutation to the list of all permutations
all.add(permutation);
// Return the updated list of permutations
return all;
}
// Iterate through the array, swapping elements at index i with elements at index j
for(int j=i; j<nums.length; j++){
// Swap elements at indices i and j to create a new permutation
swap(nums, i, j);
// Recursively generate permutations for the next element
permuteHelper(nums, i+1, all);
// Swap back elements at indices i and j to backtrack and try other possibilities
swap(nums, i, j);
}
// Return the list of permutations
return all;
}
}